Bisa Tolong Beserta Caranya

[tex]( \frac{9a {}^{2} b {}^{ - 1} c {}^{3} }{27a {}^{ - 1} b {}^{2}c {}^{2} } ) {}^{ - 1} \\ \\

= ( \frac{3 {}^{2} a {}^{2} b {}^{ - 1} c {}^{3} }{3 {}^{3} a {}^{ - 1} b {}^{2}c {}^{2} } ) {}^{ - 1}[/tex]
[pangkatnya dikali -1]
[tex]= \frac{3 {}^{ - 2} a {}^{ - 2} b {}^{ 1} c {}^{ - 3} }{3 {}^{ - 3} a {}^{ 1} b {}^{ - 2}c {}^{ - 2} } \\ = 3 {}^{ - 2 - ( - 3)} a {}^{ - 2 - 1} b {}^{1 - ( - 2)} c {}^{ - 3 - ( - 2)} \\ = 3 {}^{ - 2 + 3} a {}^{ - 2 - 1} b {}^{1 + 2} c {}^{ - 3 + 2} \\ = 3 {}^{1} a {}^{ - 3} b {}^{3} c {}^{ - 1} \\ = \frac{3b {}^{3} }{a {}^{3}c } [/tex]
Jadi, jawabannya A