Matematika

Pertanyaan

persamaam 3x-2y+z=11, 2x+3y-2z=1, x-3y+z=4. tentukan nilai dari 1/x+y+z

1 Jawaban

  • 3x - 2y + z = 11 (P1)
    2x + 3y - 2z = 1 (P2)
    x - 3y + z = 4 (P3)

    2x + 3y - 2z = 1 (P2)
    x - 3y + z = 4 (P3)
    ______________+
    3x - z = 5 (P4)

    9x - 6y + 3z = 33 (P1, dikali 3)
    2x - 6y + 2z = 8 (P3, dikali 2)
    _____________-
    7x + z = 25 (P5)

    3x - z = 5 (P4)
    7x + z = 25 (P5)
    _________+
    10x = 30
    x = 3

    3x - z = 5
    3(3) - z = 5
    -z = -4
    z = 4

    x - 3y + z = 4 (P3)
    3 - 3y + 4 = 4
    -3y = -3
    y = 1

    1/(x+y+z)
    = 1/(3+1+4)
    = 1/8

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