Please jawab pake caranya ya,penting!!!

f(x) = 1/(2x-1). dan fog(x) = x /(3x-2)
f { g(x) } = x / (3x - 2)
1 / (2g(x) -1 ) = x / (3x -2)
{ 2g(x) -1 } x = (3x -2)
2g(x) - 1 = (3x -2)/x
2g(x) = (3x -2)/x -1
2g(x) = 3x/x -2/x - x/x
2g(x) = 2 -2/x
g(x) = (2 -2/x)/2
g(x) = 1 - 1/x

jawab

f(x) =  1/(2x -1)
fog (x)  =  x/ (3x - 2)
f { g(x) } = x/  (3x - 2)
1/ ( 2. g(x) - 1) = x / (3x  - 2)
2. g(x) - 1  =  (3x - 2) /(x)
2.g(x) = (3x - 2)/(x ) + 1
2. g(x) = (3x -2 + x) / (x)
g(x) = (4x - 2) / (2x)
g(x) = 4x / 2x  - 2/2x
g(x) = 2 - 1/x
jawab C