fungsi f dirumuskan f(x)=ax+b,diketahui f(-3)=-22 dan f(10)=56,tentukan bentuk rumus fungsi f(x)

f(x) = ax + b
f(-3) = -22 dan f(10) = 56
f(x) = ax + b ---> f(-3) = a(-3) + b = -22
= -3a + b = -22 ..... 1
f(10) = a(10) + b = 56
= 10a + b = 56 ......2
-3a + b = -22
10a + b = 56
-------------------- -
-13a = -78
a = -78 / -13
a = 6

-3a + b = -22
-3(6) + b = -22
-18 + b = -22
b = -22 + 18
b = -4

f(x) = ax + b
f(x) = 6x -4

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