Matematika. Ada yang tahu cara menyelesaikan ini dengan matriks? Diketahui titik A merupakan perpotongan garis x - 2y = -10 dan 2x - 3y = -5. Garis g melalui ti

x - 2y = -10 
2x -3y = -5

x -2y = -10          2x - 3y = -5
10 - 2y = x          5 - 3y = 2x
(10-2)                 (5 - 3)² = 25 - 9                 

[tex]x-2y=-10 \\ 2x-3y=-5 \\ \left[\begin{array}{ccc}1&-2\\2&-3\end{array}\right] .\left[\begin{array}{ccc}x\\y\end{array}\right]=\left[\begin{array}{ccc}-10\\-5\end{array}\right] \\ \left[\begin{array}{ccc}x\\y\end{array}\right]=\left[\begin{array}{ccc}1&-2\\2&-3\end{array}\right]^{-1}.\left[\begin{array}{ccc}-10\\-5\end{array}\right] \\ \left[\begin{array}{ccc}x\\y\end{array}\right]= \frac{1}{-3-(-4)} \left[\begin{array}{ccc}-3&2\\-2&1\end{array}\right].\left[\begin{array}{ccc}-10\\-5\end{array}\right] [/tex]
[tex]\left[\begin{array}{ccc}x\\y\end{array}\right]= 1 \left[\begin{array}{ccc}20\\15\end{array}\right] \\ \left[\begin{array}{ccc}x\\y\end{array}\right]= \left[\begin{array}{ccc}20\\15\end{array}\right] \\ [/tex]
jadi titik A(20,15)
persamaan garis melalui A(20,15) dan B(3.4) adlh
[tex] \frac{x-x_1}{x_2-x_1} = \frac{y-y_1}{y_2-y_1} \\ \frac{x-20}{3-20} = \frac{y-15}{4-15} \\ \frac{x-20}{-17} = \frac{y-15}{-11} \\ -17y+255=-11x+220 \\ 11x-17y+255-220=0 \\ 11x-17y+35=0[/tex]
semoga membantu ya ^_^