invers dari matriks C=1. 2 5. -1

invers = 1/det C x adjoint C

= [tex] \frac{1}{-1 -10} [/tex] x [tex] \left[\begin{array}{ccc}-1&5\\2&1\end{array}\right] [/tex]
= [tex] \frac{1}{-11} [/tex] x [tex] \left[\begin{array}{ccc}-1&-5\\-2&1\end{array}\right] [/tex]
= [tex] \left[\begin{array}{ccc} \frac{1}{11} & \frac{2}{11} \\ \frac{5}{11} & \frac{1}{-11} \end{array}\right] [/tex]