jika phi 22/7, maka volume benda tersebut adalah?

jawab

benda terdiri dari tabung dan kerucut
r tabung = r kerucut = 1/2 (14) = 7 cm
t tabung = tt= 12 cm
t kerucut = tk =  18 - 12 = 6 cm

V benda = V tabung + V lerucut
VB = π r² tt  + 1/3 π r² tk
VB = π r²(tt + 1/3 tk)
VB = 22/7. 7² ( 12 + 1/3 (6))
VB = 154 (12 + 2)
VB = 154 x 14
VB = 2.156  cm³

V = V tabung + V kerucut
V = π r^2 t + 1/3 π r ^2 t
V = 22/7 × 7 × 7 × 12 + 1/3.22/7.7.7.6
V = 1.848 + 308
V = 2.156 cm3