jika fungsi kuadrat 2x² -4x +3a mempunyai nilai maksimum 1,maka 27a³ -9a=

y = 2x² - 4x + 3a

cari sb simetri
x = -b/2a
= -(-4)/2(2)
= 1

krn nilai maks 1 ,
1 = 2(1)² - 4(1) + 3a
1 = 2 - 4 + 3a
1 = -2 + 3a
3 = 3a
a = 1


27a³ - 9a
= 27(1)³ - 9(1)
= 18

f(x) = 2x² - 4x + 3a
y = 2x² -4x + 3a

[tex]y = \frac{ {b}^{2} - 4ac }{ - 4a} = 1 \\ \\ \frac{ {( - 4)}^{2} - 4 \times 2 \times 3a }{ - 4(2)} = 1 \\ \\ \frac{16 - 24a}{ - 8} = 1 \\ \\ 16 - 24a = - 8 \\ - 24a = - 24 \\ a = 1[/tex]
27a³ - 9a
= 27(1)³ - 9(1)
= 27 - 9
= 18

maaf kalo salah