Matematika

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jika f(1)=2 dan f(n+1)=(f(n))^2 barapakah nilai f (5)

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    f(1)= 2
    f(n+1) = ( f(n))²
    f(1+1) = ( f(1))² → f(2) = 2²= 4
    f(2 +1) = { f(2) }² → f(3) = 4² = 16
    f(3+1) = { f(3) }²  → f(4) = 16² = 256
    f(4+1) = { f(4) }² → f(5) = 256² = 65.536

    f(5)  = 65.536

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