ph larutan oh-=0,00004m
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dodo75
Pertanyaan
ph larutan oh-=0,00004m
1 Jawaban
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1. Jawaban Irn2000
[OH-] = 4 × 10^-5
pOH = - log 4 × 10^-5 = 5 - log 4
pH = 14 - (5 - log 4) = 9 + log 4