nilai dari [tex]{}^{2} log(12) - {}^{2} log(6) + {2}^{2} log(2)[/tex] adalah....

[tex] {}^{2} log(12) - {}^{2} log(6) + {}^{2} log(2 {}^{ \frac{1}{2} } ) \\ {}^{2} log(12) - {}^{2} log(6) + \frac{1}{2} {}^ \: {2} log(2) \\ {}^{2} log(12) - {}^{2} log(6) + \frac{1}{2} {}^ \: \times 1 \\ {}^{2} log(12) - {}^{2} log(6) + \frac{1}{2} \\ {}^{2} log( \frac{12}{6} ) + \frac{1}{2} \\ {}^{2} log(2) + \frac{1}{2} \\ = 1 + \frac{1}{2} \\ = \frac{2}{2} + \frac{1}{2} \\ = \frac{3}{2} \\ = 1.5[/tex]

Jawabannya:
2log(12)-2log(6)+2log(2 1/2)
= 2log(12)-2log(6)+1/2 2log(2)
= 2log(12)-2log(6)+1/2×1
= 2log(12/6)+1/2
= 2log(2)+1/2
= 1+1/2
= 2/2+1/2
= 3/2

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