2log3 X 3log16- 3log27+ 4log1\ 64

[tex] {}^{2} log(3) \times {}^{3} log(16) - {}^{3} log(27) + {}^{4} log( \frac{1}{64} ) \\ {}^{2} log(16) - {}^{3} log(27) + {}^{4} log \: 64 {}^{ - 1} \\ {}^{2} log(16) - {}^{3} log(27) + - 1 \times {}^{4} log \: 64 \\ = 4 - 3 - 1 \times 3 \\ = 4 - 3 - 3 \\ = - 2[/tex]


■■■■■■■■■■■■■■■■■

P.s : tulisannya digeser ya..soalnya kepanjangan

Jawabannya:
2log3×3log16-3log27+4log1/64
=2log(3)×3log(16)-3log(27)+4log(1/64)
=2log(16)-3log(27)+4log64^-1
=2log(16)-3log(27)+-1×4log64
=4-3-1×3
=4-3-3
=1-3
= -2

Semoga Membantu
Jadikan Terbaik Ya