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[tex] \frac{2}{ \sqrt{x} } + \frac{1}{ \sqrt{y} } = 11 \\ \frac{1}{ \sqrt{x} } - \frac{1}{ \sqrt{y} } = - 2 \\ - - - - - - - - \: \: \: + \\ \frac{3}{ \sqrt{x} } = 8 \\ \sqrt{x} = \frac{3}{8} \\ x = \frac{ \sqrt{3} }{ \sqrt{8} } \times \frac{ \sqrt{8} }{ \sqrt{8} } \\ x = \frac{2 \sqrt{6} }{8} \\ x = \frac{ \sqrt{6} }{4} [/tex]
[tex] \frac{2}{ \sqrt{x} } + \frac{1}{ \sqrt{y} } = 11 \\ \frac{1}{ \sqrt{x} } - \frac{1}{ \sqrt{y} } = - 2 \: \: ( \times 2) \\ \frac{2}{ \sqrt{x} } + \frac{1}{ \sqrt{y} } = 11 \\ \frac{2}{ \sqrt{x} } - \frac{2}{ \sqrt{y} } = - 4 \\ - - - - - - - - \: \: \: \: \: - \\ \frac{3}{ \sqrt{y} } = 15 \\ \sqrt{y }= \frac{3}{15} \\ y = \frac{ \sqrt{3} }{ \sqrt{15} } \times \frac{ \sqrt{15} }{ \sqrt{15} } \\ y = \frac{3 \sqrt{5} }{15} \\ y = \frac{ \sqrt{5} }{5} [/tex]

HP = {(akar6 / 4, akar5 / 5)}

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