Matematika

Pertanyaan

mohon bantuannya tolong bantu jawab?
mohon bantuannya tolong bantu jawab?

1 Jawaban

  • [1]
    a] 35 - 23x2 + 15:3 = 35 - 46 + 5 = -6
    b] 3/5 + 5/8 - 5/10 + 2 = (24+25-20+80)/40 = 109/40 = 2 29/40
    c] v18 + v64 + v50 = v9.2 + 8 + v25.2 = 3v2 + 8 + 5v2 = 8(v2 + v1)
    Ket : v dibaca akar


    [2]
     2x - y = 3
    -3x - y = 8
    ------------- (-)
    5x      = -5
      x      = -1

    2x - y = 3
    2(-1) - y = 3
    -2 - y = 3
    -y = 5
    y = -5


    [4]
    y - y1 = m(x - x1)
    y - (-3) = 2(x - 1)
    y + 3 = 2x - 2
    y - 2x - 5 = 0


    [5]
    (y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
    (y - (-2))/(-5 - (-2)) = (x - 1)/(2 - 1)
    (y + 2)/-3 = (x - 1)
    y + 2 = (x - 1)3
    y + 2 = 3x - 3
    y - 3x + 5 = 0


    [6]
    Un = 3 - 2n
    U1 = 3 - 2(1) = 1
    U2 = 3 - 2(2) = -1
    U3 = 3 - 2(3) = -3
    U4 = 3 - 2(4) = -5
    U5 = 3 - 2(5) = -7

    Jadi, suku ke 1 hingga ke 5 secara berurutan adalah 1, -1, -3, -5, dan -7


    [8]
    Diketahui :
    Barisan geometri : 2, 6, 18, 54

    Ditanya :
    a = ?
    r = ?
    U9 = ?

    Penyelesaian :
    a = U1 = 2

    U2 = 6
    ar = 6
    2r = 6
    r = 6/2 = 3

    U9 = a.r^8 = 2(3^8) = 2(6561) = 13122


    [9]
    Diketahui :
    U1 = a = 3
    U5 = -5

    Ditanya :
    S10 = ?

    Penyelesaian :
    U5 = -5
    a + 4b = -5
    3 + 4b = -5
    4b = -5 -3
    b = -8/4 = -2

    Sn = (n/2)(2a + (n-1)b)
    S10 = (10/2)(2(3) + (10-1)-2) = 5(6 - 18) = 5(-12) = -60


    [10]
    Diketahui :
    Barisan aritmetika : 2, 6, 10, 14

    Ditanya :
    U25 = ?

    Penyelesaian :
    a = U1 = 2
    b = U2 - U1 = 6 -2 = 4
    Un = a + (n-1)b
    U25 = 2 + 24(4) = 2 + 96 = 98