Penjumlahan matriks (2x+1, 2, 5, y-3)+(3, -8, 7, 10)= 2 (4, -3, 6, 6) nilai x dan y berturut turut?
Matematika
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Pertanyaan
Penjumlahan matriks (2x+1, 2, 5, y-3)+(3, -8, 7, 10)= 2 (4, -3, 6, 6) nilai x dan y berturut turut?
2 Jawaban
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1. Jawaban Luthfiyahya26
y - 3 + 10 = 2 x 6
y + 7 = 12
y = 12 - 7 = 5
2x + 1 + 3 = 2 x 4
2x + 4 = 8
2x = 4
x = 4 : 2 = 2
Bintangnya ya -
2. Jawaban fitriiahndyn
[tex] \left[\begin{array}{ccc}2x+1\\2\\5\\y-3\end{array}\right] + \left[\begin{array}{ccc}3\\-8\\7\\10\end{array}\right] = 2\left[\begin{array}{ccc}4\\-3\\6\\6\end{array}\right][/tex]
[tex]\left[\begin{array}{ccc}2x+1+3\\2-8\\5+7\\y-3+10\end{array}\right] = \left[\begin{array}{ccc}2(4)\\2(-3)\\2(6)\\2(6)\end{array}\right][/tex]
[tex]\left[\begin{array}{ccc}2x+4\\-6\\12\\y+7\end{array}\right] = \left[\begin{array}{ccc}8\\-6\\12\\12\end{array}\right][/tex]
[tex]2x + 4 = 8[/tex]
[tex]2x = 8 - 4 [/tex]
[tex]x = \frac{4}{2}=2[/tex]
[tex]y + 7 = 12[/tex]
[tex]y = 12 - 7 = 5[/tex]
Jadi, x = 2, y = 5