tolong bantuuu yang tepat

[tex] {}^{2} log(3 {x}^{2} + 5x + 6 ) - {}^{2} log(3x + 1) = 2 \\ {}^{2} log(3 {x}^{2} + 5x + 6 ) - {}^{2} log(3x + 1) = {}^{2} log( {2}^{2} ) \\ {}^{2} log( \frac{3 {x}^{2} + 5x + 6 }{3x + 1} ) = {}^{2} log( {2}^{2} ) \\ \frac{ {3x}^{2} + 5x + + 6}{3x + 1} = {2}^{2} \\ {3x}^{2} + 5x + 6 = 4(3x + 1) \\ {3x}^{2} + 5x + 6 = 12x + 4 \\ {3x}^{2} + 5x + 6 - 12x - 4 = 0 \\ {3x}^{2} - 7x + 2 = 0 \\ \\ log{x}^{2} \leqslant log(2x + 5) + log( {2}^{2} ) \\ log( {x}^{2} ) \leqslant log((2x + 5)(4)) \\ log( {x}^{2} ) \leqslant log(8x + 20) \\ {x}^{2} \leqslant 8x + 20 \\ {x}^{2} - 8x - 20 \leqslant 0 \\ (x - 10)(x + 2) \leqslant 0 \\ x = 10 \: atau \: x = - 2 \leqslant 0 \\ hp = x \leqslant - 2 \: atau \: x \geqslant 10[/tex]