jika sin a=3/5 dan tan b=4/3,sudut a dan b lancip,tentukan nilai sin(a+b)+sin (a-b)=

Dik
Sin a = 3/5, cos a = 4/5
Tan b = 4/3, sin b = 4/5, cos b = 3/5
• sin(a+b) = sin a cos b + sin b cos a
= (3/5)(3/5)+(4/5)(4/5)
= (6/5)+(8/5)
= 14/5
• sin(a-b) = Sin a cos b - sin b cos a
= (3/5)(3/5)-(4/5)(4/5)
= (6/5)-(8/5)
= -2/5
• sin(a+b)+sin(a-b) = (14/5)+(-2/5)
= 12/5