I.4ײ-9=(2×+3)(2×3) II.2ײ+×+3=(2×-3)(×+1) III.ײ+×-6=(×+3)(×-2) IV.ײ+4×-5=(×-5)(×+1) tolong kak bsk dikumpul :(

I.4ײ-9=(2×+3)(2×3) (??)
 kalo 4ײ-9=(2×+3)(2×+3)
 4x²-9 = 4x²+12x+9
4x²-4x²-12x=9+9
-12x = 18
x = 18/(-12)= -1,5

II.2ײ+×+3=(2×-3)(×+1)
2x²+x+3 = 2x²-x-3
2x²-2x²+x+x = -3(-3)
2x = -6
x = -3

III.ײ+×-6=(×+3)(×-2)
x²+x-6 = x²+x-6

IV.ײ+4×-5=(×-5)(×+1)
x²+4x-5 = x²-4x-5
x²-x²+4x+4x = -5+5
8x = 0
x = 0