2 log3 - 2 log24 + 2 log16 adalah?

[tex] = 2 log(3) - 2 log(24) + 2 log(16) \\ = 2 log(3) - 2 log( {2}^{3} \times 3) + 2 log( {2}^{4} ) \\ = 3 \times 4(2 log(3) - 2 log(2) + 2 log(3) + 2 log(2) ) \\ = 12(2 \times 2 log(3) - 1 + 1) \\ = 12 \times 2 \\ = 24[/tex]
semoga membantu!