brainly diketahui fungsi f(x)=mx+n.jika f(-2)=1 dan f(1)=10 tentukan: rumus fungsi f(x)

f(x) = mx+n
f(-2) = 1
f(1) = 10

maka f(x)

f(-2) = -2m + n = 1
f(1) = m + n = 10

elimininasikan f(-2) dan f(1)

f(-2) = -2m + n = 1
f(1) = m + n = 10

-3m = -9
m = 3

f(1) = m + n = 10
f(1) = 3 + n = 10
f(1) = n = 7

maka m = 3 dan n = 7

sehingga f(x) = 3x + 7



pembuktian :

f(-2) = -2m + n = 1
f(-2) = -2.3 + 7 = 1
f(-2) = -6 + 7 = 1

f(1) = m + n = 10
f(1) = 3 + 7 = 10

f(x) = mx +n
f ?( -2)=1 maka f(-2) = m ( -2) + n =1
-2m + n = 1 ---> persaman 2
f( 1) =10 maka f ( 1) = m ( 1) + n = 10
n = 10 - m ---> persamaan 2
substitusikan persamaab 2 ke persamaan 1
-2m + ( 10 - m ) = 1
-2m + 10 - m = 1
-2m - m = 1 - 10
-3m = -9
m = -9 / -3
m = 3
substansikan m = 3 ke persamaan 2
n = 10 - m
n = 10 - 3
n = 7
jadi nilai m = 3 dan nilai n = 7 maka rumus fungsinya :
f ( x ) = mx + n
f ( x ) = 3x + 7