Matematika

Pertanyaan

himpunan penyelesaian dari 2a+3b+4c=1,a+3b+2c=-1 dan 4a+4b+9c=-2

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  • 2a + 3b + 4c = 1
    a + 3b + 2c = - 1
    4a + 4b + 9c = - 2
    ______________

    2a + 3b + 4c = 1
    a + 3b + 2c = - 1
    ____________ -
    a + 2c = 2

    a + 3b + 2c = - 1 |×4
    4a + 4b + 9c = - 2 |×3
    ________________
    4a + 12b + 8c = - 4
    12a + 12b + 27c = - 6
    ________________ -
    -8a - 19c = 2

    a + 2c = 2 |×8
    -8a - 19c = 2 |×1
    _____________
    8a + 16c = 16
    -8a - 19c = 2
    ___________ +
    - 3c = 18
    c = - 6

    Substitusi persamaan 4
    a + 2c = 2
    a + 2(-6) = 2
    a - 12 = 2
    a = 14
    Substitusi persamaan 1

    2a + 3b + 4c = 1
    2(14) + 3b + 4(-6) = 1
    28 + 3b - 24 = 1
    4 + 3b = 1
    3b = - 3
    b = - 1
    Hp = {14, - 1, - 6}

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