Tolong kerjakan soal nomor 1 dan 2.. Terimakasih

1. (x-3)^2 = (2x-1)^2
(x-3) (x-3) = (2x-1) (2x-1)
x^2-3x-3x+9 = 4x^2-2x-2x+1
x^2-6x+9 = 4x^2-4x+1
x^2-4x^2-6x+4x+9-1 = 0
-3x^2-2x+8 = 0
(3x+4) (-x+2) = 0
x = -4/3 atau x = 2

2. 2x-3 > 1(x-5)
2x-3 > x-5
2x-x > -5+3
x > -2