Nilai Maksimum fungsi objektif z = 3x + y yang memenuhi sistem pertidaksamaan 4x + 3y ≤ 12 ; 4x + y ≤ 8 ; x ≥ 0 ; y ≥ 0 !

1. 4x+3y ≤ 12 => x = 3, y = 4
2. 4x+y ≤ 8 => x = 2, y = 8
3. perpotongan 4x+3y ≤ 12 dan 4x+y ≤ 8

4x+3y = 12
4x+y = 8
________ _
2y = 4
y = 2

4x+y = 8
4x+(2) = 8
4x = 6
x = 6/4 = 3/2

x = 3/2
y = 2

fungsi objektif z = 3x+y
fungsi (3,4) = 3(3)+4 = 9+4 = 13
fungsi (2,8) = 3(2)+8 = 6+8 = 14
fungsi (3/2,2) = 3(3/2)+2 = 9/2+2 = 9/2+4/2 = 13/2 = 6,5

Nilai maksimum = 14

semoga membantu yaa:)