tolong di bantu kak buat hari ini soalnya

16.]
(½)²ˣ⁺¹ > √[ 8 / 2ˣ⁻¹]
(½)²ˣ⁺¹ > √[ 2³⁻⁽ˣ ⁻ ¹⁾]
(½)²ˣ⁺¹ > √[ 2⁴⁻ˣ]
(2)⁻²ˣ⁻¹ > 2^{½ (4 - x)}
-2x - 1 > ½(4 - x)
-2x - 1 > 2 - ½ x
-³/₂ x > 3 [× -2]
3x < -6
x < -2
[B]

17.]
log (x² + 9x + 5) = 1
x² + 9x + 5 = 10
x² + 9x - 5 = 0

x₁ + x₂ = -b / a = -9
[A]

18.]
log x + log(x - 3) = 1
log x(x - 3) = log 10
x² - 3x = 10
x² - 3x - 10 = 0
(x - 5)(x + 2) = 0
x = -2 atau x = 5 ... (i)

Syarat
x - 3 > 0
x > 3 ... (ii)

Irisan dari (i) dan (ii) adalah HP-nya
HP : { 5 }

19.]
log (∛2 × √2)
= log ∛2 + log √2
= log 2^{⅓} + log 2^{½}
= (⅓ × log 2) + (½ × log 2)
= (⅓ + ½) × log 2
= ⅚ × 0,3010
= 0,2508
[ - ]

20.]
²log 27 × ⁹log5 × ²⁵log ¹/₁₆
= ²log 3³ × [tex] ^{3^2} \log 5 \times ^{5^2} \log 2^{-4} [/tex]
= 3 × ²log 3 × ½ × ³log 5 × (-2) × ⁵log 2
= -3 × ²log 2
= -3
[A]

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