Matematika

Pertanyaan

Tolong dibantu kak soalnya buat hari ini
Tolong dibantu kak soalnya buat hari ini

1 Jawaban

  • 12.]
    [tex] 3^{2x + y} = \frac{1}{81} \\
    3^{2x+y} = 3^{-4} [/tex]
    2x + y = -4
    y = -4 - 2x ... (i)

    x² + 5y = 16 , Subt. persamaan (ii)
    x² + 5(-4 - 2x) = 16
    x² - 20 - 10x = 16
    x² - 10x - 36 = 0

    x₁ + x₂ = -b/a = 10
    [A]

    13.]
    3³⁻ˣ + 3ˣ = 12
    3³ / 3ˣ + 3ˣ = 12 [× 3ˣ]
    27 + (3ˣ)² = 12 × 3ˣ
    (3ˣ)² - (12 × 3ˣ) + 27 = 0
    (3ˣ - 9)(3ˣ - 3) = 0
    3ˣ = 9 atau 3ˣ = 3
    x = 2 atau x = 1

    x₂ - x₁ = 1 - 2 = -1
    [C]

    14.]
    2ˣ⁺¹ ≥ (⅛)ˣ⁻³
    2ˣ⁺¹ ≥ (2⁻³)ˣ⁻³
    x + 1 ≥ -3x + 9
    4x ≥ 8
    x ≥ 2
    [D]

    15.]
    [tex] (\frac{1}{27})^{x^2 - x} < (\frac19)^{x + 1} \\
    (3^{-3(x^2-x)} < (3^{-2(x + 1)} [/tex]
    -3(x² - x) < -2(x + 1)
    -3x² + 3x < -2x - 2
    -3x² + 5x + 2 < 0
    3x² - 5x - 2 > 0
    (3x + 1)(x - 2) > 0
    x < - ⅓ atau x > 2
    [C]