Tolong dibantu dong dua soal ini soalnya susah makasih

No. 1
BF / CF = AB / EF
10 / 15 = 12 / EF
10.EF = 12 × 15
10.EF = 180
EF = 180 / 10
EF = 18

BF / CF = EF / CD
10 / 15 = 18 / CD
10.CD = 18 × 15
10.CD = 270
CD = 270 / 10
CD = 27

CD - EF = 27 - 18 = 9
Tinggi Trapesium adlah DE

[tex]DE= \sqrt{(CF)^{2} - (CD-EF)^{2}} \\ \\ DE= \sqrt{15^{2} - 9^{2}} \\ \\ DE= \sqrt{225 - 81} \\ \\ DE= \sqrt{144} = 12 \\ \\ \\ Luas\ Trapesium \\ \\ L= \frac{1}{2}.(EF + CD).(DE) \\ \\ L= \frac{1}{2}.(18 + 27).(12)\\ \\ L= \frac{1}{2}.(45).(12)\\ \\ L= (45).(6) \\ \\ L= 270 \\ \\ Luas\ Trapesium\ EFCD\ adalah\ 270\ cm^{2}[/tex]

No. 2
[tex]Tinggi\ Kerucut = \sqrt{s^{2} -r^{2}} \\ Tinggi\ Kerucut = \sqrt{25^{2} -7^{2}} \\ Tinggi\ Kerucut = \sqrt{625 -49} \\ Tinggi\ Kerucut = \sqrt{576} \\ Tinggi\ Kerucut = 24 \\ \\ Volume\ Bandul=Volume\ \frac{1}{2}\ Bola+Volume\ Kerucut \\ \\ V_{B} =( \frac{1}{2}. \frac{4}{3}. \pi .r^{3})+( \frac{1}{3}. \pi .r^{2}.t) \\ \\ V_{B} =( \frac{1}{2}. \frac{4}{3}. \frac{22}{7}.7^{3})+( \frac{1}{3}.\frac{22}{7}.7^{2}.24) \\ \\ V_{B} = (\frac{(2).(22).(49)}{3} ) +((22).(7).(8))[/tex]

[tex]V_{B} = (\frac{(2).(22).(49)}{3} ) +((22).(7).(8)) \\ \\V_{B} =718 \frac{2}{3}+ 1232 \\ \\ V_{B} = 1950 \frac{2}{3}\ cm^{3} [/tex]