Jika 2log7 = a maka 49log 8=

²log7 = a

⁴⁹log8
= (7²) log2³
= (3/2) . ⁷log2
= (3/2) . (1/a)
= 3/(2a)
= [tex] \frac{3}{2a} [/tex]

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

^49log 8
= ²log 8 : ²log 49
= (²log 2^3) : (²log 7²)
= (3 . ²log 2) : (2 . a)
= 3/2a