Tolong bantu pertanyaanku kak

[tex]( \frac{1}{ \sqrt{2} } )^{x+1}=( \sqrt{2 \sqrt{2} } )^{4x}\\( \sqrt{2} )^{-x-1}=(2 \sqrt{2} )^{2x}\\2^{- \frac{1}{2}x- \frac{1}{2} }=2^{2x} \ \ 2^{x}\\2^{- \frac{1}{2}x- \frac{1}{2} }=2^{3x}\\ \frac{-(x+1)}{2}=3x\\x+1=-6x\\7x=-1\\x= -\frac{1}{7} [/tex]