tolong bantu jawab ya sama pakai jalan

[tex] {3}^{2x + 2} + 8. {3}^{x} - 1 = 0 \\ ( { {3}^{x}) }^{2} .{3}^{2} + 8. {3}^{x} - 1 = 0 \\ misal \: {3}^{x} = y \\ 9{y}^{2} + 8y - 1 = 0 \\ (9y - 1)(9y + 9) = 0 \\ (9y - 1)(y + 1) = 0 \\ y = \frac{1}{9} \: atau \: y = - 1 \\ \\ y = \frac{1}{9} \\ {3}^{x} = \frac{1}{9} \\ {3}^{ - 2} = \frac{1}{9} \\ x = - 2 \\ \\ y = - 1 \: tdk \: ada \: penyelesian \: \\ \\ hp = x = - 2[/tex]
B