tolong bantuin ya nomor 27 sama 28 ga ngerti tentang akar sama dengan caranya juga ya terima kasih

no. 27

[tex]ab \: = \sqrt{b d\times bc} \\ ab = \sqrt{7 \times 11} \\ a b \: = \sqrt{77} [/tex]

27.)
BD = 7 dan DC = 4
BC = BD + DC = 7 + 4 = 11
Jadi,
AB = √(BD×BC) = √(7×11) = √77

28.)
PS = 3 dan SQ = 8
PQ = PS + SQ = 3 + 8 = 11
PQ = alas segitiga

RS = √(PS×SQ) = √(3×8) = √24
RS = tinggi segitiga

Luas ∆PQR =
(1/2) × alas × tinggi =
(1/2) × PQ × RS =
(1/2) × 11 × √24 = 11/2 √24 = 5 1/2 √24 (A)