tolong yang nomor 10 dan 11 beserta caranya

[tex] {9}^{2x - \frac{3}{2} } = \frac{1}{3} {}^{ - {x}^{2} } \\ {3}^{2(2x - \frac{3}{2} )} = {3}^{ - 1( - {x}^{2} )} \\ {3}^{4x - 3} = {3}^{ {x}^{2} } \\ 4x - 3 = {x}^{2} \\ 0 = {x}^{2} - 4x + 3 \\ 0 = (x - 1)(x - 3) \\ \\ jadi \: x = 1 \: atau \: x = 3[/tex]