Matematika

Pertanyaan

y=sin^2 (x+1) cos x

tentukan d^2y / d^x

d = diferensial parsil

1 Jawaban

  • y' = u'v - uv'
    u = sin^2 (x+1)
    u' = d sin^2 (x+1)/ d sin (x+1) * d sin
    (x+1)/ d (x+1) * d (x+1)/d (x)
    u' = 2sin(x+1) * cos(x+1) * 1
    u' = sin2(x+1)
    v = cos x
    v' = -sin x
    y' = (sin2(x+1)cosx) - (-sin^2(x+1)sinx)
    y' = sin2(x+1)cosx + sinx sin^2(x+1)

Pertanyaan Lainnya