nomor 5-6 caranya dong kakak:( ga ngerti beneran

jawab

(5)

[tex] (7)^{ x^{2}+x-6}\, =\, (\frac{1}{49})^{x-2} [/tex]

[tex] (7)^{ x^{2}+x-6}\, =\, (7^{-2}})^{x-2} [/tex]

[tex] x^{2}+x -6}\, =\, -2 ({x-2})[/tex]

x² + x - 6 = -2x + 4 = 0
x² + x  + 2x - 6 - 4 = 0
x² + 3x - 10 =0
(x + 5)(x - 2) =0
x = - 5  atau x = 2

(6) f(x) = 1

[tex]( \frac{1}{3})^{2x^2 -7x +6} = 1 = ( \frac{1}{3})^{0} [/tex]

2x² -  7x  + 6 = 0
(2x - 1)(x - 3) =0
x = 1/2  atau x = 3