Matematika

Pertanyaan

diketahui SPNTLV berikut

1/x + 1/y - 1/z = 6
2/x - 3/y + 1/z = 5
1/z - 1/y = -1

tentukan nilai :
a. x, y dan z
b. 2/x + 1/y - 3/z =........


tolong di jb...
bsok d kumpul

1 Jawaban

  • ( a )

    1/x + 1/y - 1/z = 6 |×2 | 2/x + 2/y - 2/z = 12
    2/x - 3/y + 1/z = 5 |×1 | 2/x - 3/y + 1/z = 5
    1/z - 1/y = -1 |×1 | 1/z - 1/y = -1
    —:
    5/y - 3/z = 7 | ×1 | 5/y - 3/z = 7
    -1/y + 1/z = -1 | ×-5 | 5/y - 5/z = 5
    —:
    2/z = 12
    z = 2/12 → 1/z = 6
    —:
    1/z - 1/y = -1
    1/(2/12) - 1/y = -1
    12/2 - 1/y = -1
    -1/y = -1 + 6
    -1/y = 5
    y = -1/5 → 1/y = -5
    —:
    1/x + 1/y - 1/z = 6
    1/x - 5 + 6 = 6
    1/x = 5
    x = 1/5

    jadi
    x = 1/5
    y = -1/5
    z = 1/6

    ( b ) 2/x + 1/y - 3/z = ....

    2(5) + (-5) - 3(6) = ....

    10 - 5 - 18 = -13

    semoga membantu

    tolong jadikan jawaban ter-brianly ya :)

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